Find the second leg of a right-angled triangle if its hypotenuse is 17 cm, and the other leg is 15 cm.

Consider a triangle ABC.
AC = a, BC = b – legs
AB = c – hypotenuse
angle ACB – straight

AC = 15 cm
AB – 17 cm

By the Pythagorean theorem:
c ^ 2 = a ^ 2 + b ^ 2
AB ^ 2 = AC ^ 2 + BC ^ 2
17 ^ 2 = 15 ^ 2 + BC ^ 2
17 ^ 2 – 15 ^ 2 = BC ^ 2
(17-15) (17 + 15) = BC ^ 2
2 * 32 = BC ^ 2
64 = BC ^ 2
BC = √ 64
BC = 8
Answer: 8 cm




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