Find the sides of the parallelogram P = 54cm, and one of the sides is 7cm less than the other.

Let 1 side be equal to a, and the second equal to b. Then the perimeter is = 2a + 2b.
By condition, one side is 7 cm less than the other.So side a = (b-7)
P = 2b + 2 (b-7)
54 = 2 * (b + b-7)
27 = 2b-7
2b = 34
b = 17
Then a = 10

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