1. If the natural number N is composite, then it contains at least two prime divisors, which may coincide.
2. Since, according to the problem statement, the number N is not divisible by any number from 2 to 12, the smallest prime divisor will be the prime number 13. And the smallest composite number will be obtained if both divisors are the number 13, i.e. 13 to the second degree:
N = 13 ^ 2 = 169.
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