Find the smallest number other than 1, which when divided by 2, 3, 4, 5, 6, 8, 9 gives the remainder 1?
| July 27, 2021 | education
To rephrase the task, it turns out that you need to find out the least common multiple (LCM) (2, 3, 4, 5, 6, 8, 9) + 1.
The solution of the problem:
1. LCM (2, 3, 4, 5, 6, 8, 9) = 2 * 3 * 2 * 5 * 2 * 3 = 360.
2.360 + 1 = 361.
Answer: 361 is the smallest number that, when divided by 2, 3, 4, 5, 6, 8, 9, gives the remainder 1.
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