The sweep area of the cube will be equal to its surface area.
Since a cube has 6 faces, its surface area is S = 6 * a², where a is the edge of the cube.
The volume of the cube is V = a³. By the condition of the problem, V = 1 61/64 = 125/64, which means
a = ³√ 125/64 = 5/4.
Thus, the unfolded area of this cube will be equal to:
S = 6 * (5/4) ² = 6 * 25/16 = 150/16 = 9 6/16 = 9 3/8 m2.
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