Find the unfolded area of a cube if its volume is 1 whole 61/64 m3.

The sweep area of the cube will be equal to its surface area.

Since a cube has 6 faces, its surface area is S = 6 * a², where a is the edge of the cube.

The volume of the cube is V = a³. By the condition of the problem, V = 1 61/64 = 125/64, which means

a = ³√ 125/64 = 5/4.

Thus, the unfolded area of this cube will be equal to:

S = 6 * (5/4) ² = 6 * 25/16 = 150/16 = 9 6/16 = 9 3/8 m2.



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