Find the values of the quadratic function y = 0.5×2-x + 1 for- x = 0, x = -1, x = -2, x = 4

y = 0.5x ^ 2 – x + 1.

Let us find the value of the function at x = 0. To do this, substitute instead of x the number “0” into the equation of the function:

y (0) = 0.5 * 0 ^ 2 – 0 + 1 = 0 – 0 + 1 = 1.

Find the value of the function at x = -1. To do this, substitute instead of x the number “-1” in the equation of the function:

y (-1) = 0.5 * (-1) ^ 2 – (-1) + 1 = 0.5 * 1 + 1 + 1 = 0.5 + 2 = 2.5.

Find the value of the function at x = -2. To do this, substitute the number “-2” instead of x in the equation of the function:

y (-2) = 0.5 * (-2) ^ 2 – (-2) + 1 = 0.5 * 4 + 2 + 1 = 2 + 3 = 5.

Find the value of the function at x = 4. To do this, substitute the number “4” instead of x in the equation of the function:

y (4) = 0.5 * 4 ^ 2 – 4 + 1 = 0.5 * 16 – 4 + 1 = 8 – 3 = 5.

Answer: 1; 2.5; 5; 5.



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