Find the volume of butane if 176 g of carbon dioxide was released during its combustion.

The reaction equation for the combustion of butane is as follows

2 С4Н10 + 9 О2 = 4 СО2 + 10 Н2О

Based on the reaction equation, it can be seen that the amount of butane substance is two times less than the amount of carbon dioxide. (4 mol: 2 mol = 2)

Let’s calculate how much carbon dioxide is released. Molar mass of carbon dioxide = 44 g / mol.

N = 176/44 = 4 mol of carbon dioxide was released.

Accordingly, the amount of butane substance will be 2 times less: 4/2 = 2 mol.

According to Avogadro’s law, 1 mole of any gas under normal conditions. occupies a volume of 22.4 liters. Therefore, 2 moles of butane will take 22.4 * 2 = 44.8 liters

Answer: the volume of butane is 44.8 liters