Find the volume of carbon dioxide and the amount of calcium chloride that is formed
July 25, 2021 | education
| Find the volume of carbon dioxide and the amount of calcium chloride that is formed by the interaction of 15 g of calcium carbonate with hydrochloric acid.
1. Let’s write down the reaction equation:
CaCO3 + 2HCl = CaCl2 + CO2 + H2O.
2. Find the amount of reacted calcium carbonate:
n (CaCO3) = m (CaCO3) / M (CaCO3) = 15 g / 100 g / mol = 0.15 mol.
3. According to the reaction equation, we find the amount of calcium chloride, as well as the volume of carbon dioxide (Vm – molar volume, constant equal to 22.4 l / mol):
n (CaCl2) = n (CaCO3) = 0.15 mol.
n (CO2) = n (CaCO3) = 0.15 mol.
V (CO2) = n (CO2) * Vm = 0.15 mol * 22.4 l / mol = 3.36 l.
Answer: n (CaCl2) = 0.15 mol; V (CO2) = 3.36 l.
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