Find the volume of hydrogen n, y released during the interaction of zinc with sulfuric acid

Find the volume of hydrogen n, y released during the interaction of zinc with sulfuric acid in the amount of a substance of 0.5 mol.

Zn + H2SO → H2 ↑ + ZnSO4.

Formula required to solve: n = V / Vm; Vm = 22.4 L / mol.

The amount of sulfuric acid substance is equal to the amount of hydrogen substance that is released during the reaction.
n (H2SO4) = n (H2) = 0.5 mol.
V (H2) = n * Vm = 0.5 mol * (22.4 l / mol) = 11.2 l.

Answer: V (H2) = 11.2 liters.




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