Find the x coordinate of the car at the moment of time 3.5 and 8 s, if its initial coordinate x0 = 30 m

Find the x coordinate of the car at the moment of time 3.5 and 8 s, if its initial coordinate x0 = 30 m, the value of the initial speed v0 = 10 m / s, and the value of acceleration a = 3 M / s.

t1 = 3.5 s.

t2 = 8 s.

X0 = 30 m.

V0 = 10 m / s.

a = 3 m / s ^ 2.

X1 -?

X2 -?

The coordinate of the body X (t) with uniformly accelerated motion depends on the time t by the following dependence: X (t) = X0 + V0 * t + a * t ^ 2/2, where X0 is the initial coordinate of the body, V0 is the initial speed of motion, a – acceleration of movement.

For this problem, the coordinate dependence will have the form: X (t) = 30 + 10 * t + 3 * t ^ 2/2.

X1 (t1) = 30 m + 10 m / s * 3.5 s + 3 m / s ^ 2 * (3.5 s) ^ 2/2 = 83.375 m.

X2 (t2) = 30 m + 10 m / s * 8 s + 3 m / s ^ 2 * (8 s) ^ 2/2 = 206 m.

Answer: X1 = 83.375 m, X2 = 206 m.



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