For pentin-1, write the formulas: a) homologue, b) carbon chain isomer, c) isomer of the position

For pentin-1, write the formulas: a) homologue, b) carbon chain isomer, c) isomer of the position of the multiple bond, d) interclass isomer

H3C – CH2 – CH2 – C ≡ CH (pentin -1).

Multiple bond position isomer:

Н3С – СН2 – С ≡ С – СН3 (pentin -2).

Homologue – butin – 1.

Н3С – СН2 – С СН (butyne -1).

Interclass isomer.

H3C – CH2 – CH2 = C = CH2 (pentadiene 1,2).

H3C – CH2 = CH – CH = CH2 (pentadiene 1,3).

Carbon chain isomer.

Н3С – СН (СН3) – С СН (3 -methylbutene -1).



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