For pentin-1, write the formulas: a) homologue, b) carbon chain isomer, c) isomer of the position
September 20, 2021 | education
| For pentin-1, write the formulas: a) homologue, b) carbon chain isomer, c) isomer of the position of the multiple bond, d) interclass isomer
H3C – CH2 – CH2 – C ≡ CH (pentin -1).
Multiple bond position isomer:
Н3С – СН2 – С ≡ С – СН3 (pentin -2).
Homologue – butin – 1.
Н3С – СН2 – С СН (butyne -1).
Interclass isomer.
H3C – CH2 – CH2 = C = CH2 (pentadiene 1,2).
H3C – CH2 = CH – CH = CH2 (pentadiene 1,3).
Carbon chain isomer.
Н3С – СН (СН3) – С СН (3 -methylbutene -1).
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