From a height of 10 m from the surface of the earth, a ball was thrown vertically upward at a speed of 20 m / s.

From a height of 10 m from the surface of the earth, a ball was thrown vertically upward at a speed of 20 m / s. At what distance from the ground will the ball be located in 2 seconds?

Distance the ball will be at:

S = h + V0 * t + a * t² / 2, where h is the initial height of the ball above the ground (h = 10 m), V0 is the initial velocity of the ball when thrown (V0 = 20 m / s), t is the time of the ball in flight (t = 2 s), a is the acceleration with which the ball moves (a = -g = -10 m / s², the movement is equally slow).

S = h + V0 * t – g * t² / 2.

Let’s do the calculation:

S = 10 + 20 * 2 – 10 * 2² / 2 = 10 + 40 – 20 = 30 m.

Answer: After 2 seconds, the ball will be 30 m above the ground.