# From point A to point B, a pedestrian simultaneously went out and a cyclist left, whose speed was 2.5 times

**From point A to point B, a pedestrian simultaneously went out and a cyclist left, whose speed was 2.5 times higher than the speed of a pedestrian. After 2.2 hours, he overtook the pedestrian by 19.8 km. Determine the speed of the pedestrian.**

Let’s designate the speed of the pedestrian as x km / h.

Then the speed of the cyclist is 2.5 km / h.

Since a pedestrian and a cyclist are moving in the same direction, the distance between them increases at a speed equal to the difference between their own speeds and is 2.5x – x = 1.5x km / h.

The distance is equal to the product of time and speed, so after 2.2 hours the distance between the cyclist and the pedestrian will be 1.5x * 2.2 = 3.3x km.

According to the condition of the problem, in 2.2 hours the cyclist overtook the pedestrian by 19.8 km, we will compose and solve the equation:

3.3x = 19.8;

x = 6.

So, the walking speed is 6 km / h.

Answer: 6 km / h.