From the vertex of the right angle MOK, two beams OP and ON are drawn so that the angle MON

From the vertex of the right angle MOK, two beams OP and ON are drawn so that the angle MON = 64 degrees, the angle POK = 57 degrees. Calculate the PON angle

Given:
angle MOK = 90 degrees,
beam ON divides the angle of the IOC into two angles MON and NOK,
angle MON = 64 degrees,
angle POK = 57 degrees.
Find the value of the angle PON -?
Solution:
Consider the IOC angle. Since the ON beam divides the MOC angle into two angles MON and NOK, then the MOC angle = MON angle + NOK angle.
Angle NOK = angle MOK – angle MON;
angle NOK = 90 – 64;
angle NOK = 26 degrees.
PON angle = NOK angle + POK angle;
angle PON = 26 + 57;
angle PON = 83 degrees.
Answer: 83 degrees.



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