Gas occupies a volume of 2 m3 at a temperature of 0 degrees Celsius.

Gas occupies a volume of 2 m3 at a temperature of 0 degrees Celsius. What will its volume be at a temperature of 27 degrees Celsius and the same pressure?

V1 = 2 m3.

t1 = 0 ° C.

t2 = 27 ° C.

P = const.

V2 -?

For a constant mass of gas, at a constant pressure, an isobaric process occurs, which is described by the Gay-Lussac law: the ratio of the volume of gas V to its absolute temperature T remains constant.

V1 / T1 = V2 / T2.

V2 = V1 * T2 / T1.

We express the absolute temperature by the formula: T = t + T.

T1 = t1 + 273.

T1 = 0 ° C + 273 = 273 ° K.

T2 = t2 + 273.

T2 = 27 ° C + 273 = 300 ° K.

V2 = 2 m3 * 300 ° K / 273 ° K = 2.2 m3.

Answer: the gas volume will increase to V2 = 2.2 m3.

One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.