# Get 50 g of potassium hydroxide from 47 g of potassium oxide, calculate the mass fraction of the product yield.

August 31, 2021 | education

| To solve, we write down the equation, select the coefficients:

K2O + H2O = 2KOH – hydration reaction, obtained potassium hydroxide;

M (K2O) = 94.2 g / mol;

M (KOH) = 56.1 g / mol.

Determine the amount of mol of potassium oxide, if the mass is known:

Y (K2O) = m / M = 47 / 94.2 = 0.498 mol.

Let’s make the proportion:

0.498 mol (K2O) – X mol (KOH);

-1 mol -2 mol hence, X mol (KOH) = 0.498 * 2/1 = 0.997 mol.

Find the theoretical mass of potassium hydroxide:

m (KOH) = Y * M = 0.997 * 56.1 = 55.97 g.

Let’s calculate the mass fraction of the product yield:

W = m (practical) / m (theoretical) * 100 = 50 / 55.97 * 100 = 89.33%.

Answer: W (KOH) is 89.33%.

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