Given a right-angled triangle ABC with legs AB = 16 cm and BC = 12 cm. Line SC 20 cm perpendicular to plane ABC Find the angle between line SA and plane ABC.
First, let’s draw a triangle ABC, in which angle B is straight.
Since in the problem a triangle ABC with legs AB = 16 cm and BC = 12 cm is given, then according to the Pythagorean theorem the hypotenuse AC = √ 16 * 16 + 12 * 12 = 20 cm.
Consider a triangle SAС, in which CA = SC = 20 cm, then such a triangle is isosceles, then the angle between the straight line SA and the plane ABC is 90/2 = 45о.
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