Gold can be flattened to a thickness of 0.10 microns. What surface area can be covered with a 2.0 g gold sheet?

Initial data: h (thickness to which gold can be flattened) = 0.1 microns (0.1 * 10-6 m); m (mass of the taken piece of gold) = 2 g (2 * 10-3 kg).

Reference values: ρz (gold density) = 19,300 kg / m3.

1) The volume of a sheet of gold taken: V = m / ρz = 2 * 10-3 / 19300 ≈ 1.04 * 10-7 m3.

2) The area that can be covered with a leaf: S = V / h = 1.04 * 10-7 / (0.1 * 10-6) = 1.04 m2.

Answer: By flattening the taken piece of gold, you can cover an area of 1.04 m2.




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