Gravity Ft and lift Fp act on the plane in the vertical direction, and the thrust F and air drag force Fc in the horizontal direction. The moduli of these forces, respectively, are equal to 545, 550, 162 and 150 kN. Find the resultant (in magnitude and direction).
Fт = 545 kN – gravity acting on the aircraft in the vertical direction;
Fп = 550 kN – lifting force acting on the aircraft in the vertical direction;
F = 162 kN – traction force acting on the aircraft in the horizontal direction;
Fс = 150 kN – air resistance force acting on the aircraft in the horizontal direction.
It is required to find the resultant forces F1 and F2.
In the vertical direction:
The force of gravity Fт is directed downwards, and the lifting force Fп is directed upwards. The resultant of these forces will be:
F1 = Fп – Fт = 550 – 545 = 5 kN.
In the horizontal direction:
The thrust force F is directed forward, and the air resistance force Fc is directed backward. The resulting force will be:
F2 = F – Fc = 162 – 150 = 12 kN.
Answer: the resultant forces are 5 kN in the vertical direction and 12 kN in the horizontal direction. That is, the nature of the plane moves forward and upward.