# How many degrees will 10 kg of water be heated by the heat released during condensation of 1 kg of steam?

Given:

m1 = 10 kilograms is the mass of water;

m2 = 1 kilogram – steam mass;

c = 4200 J / (kg * C) – specific heat capacity of water;

q = 2260 * 10 ^ 3 J / kg – specific heat of vaporization (condensation) of water.

It is required to determine dt (degree Celsius) – how many degrees the water will be heated due to the energy obtained during the condensation of water vapor.

During condensation of water vapor, energy will be released equal to:

E = q * m2 = 2260 * 10 ^ 3 * 1 = 2260000 Joules.

Then, the temperature change will be equal to:

dt = E / (c * m1) = 2260000 / (4200 * 10) = 2260000/42000 = 2260/42 = 53.8 ° C (the result has been rounded to one decimal place).

Answer: The water will heat up to 53.8 ° Celsius.

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