How many degrees will the temperature of four liters of water, which was transferred to the amount

How many degrees will the temperature of four liters of water, which was transferred to the amount of heat equal to 168 kJ, increase? (from water = 1000 kg / m³, from water = 4190 J / kg ° С)

Initial data: V (volume of water) = 4 l = 4 * 10 ^ -3 m ^ 3; Q (amount of heat transferred to water) = 168 kJ = 168 * 10 ^ 3 J.

Reference data: according to the condition ρ (water density) = 1000 kg / m ^ 3; C (specific heat capacity of water) = 4190 J / (kg * K).

The increase in water temperature can be calculated from the formula: Q = C * m * Δt, where m (water mass) = V * ρ.

Q = C * V * ρ * Δt and Δt = Q / (C * V * ρ).

Let’s calculate: Δt = 168 * 10 ^ 3 / (4190 * 4 * 10 ^ -3 * 1000) ≈ 10 ºС.

Answer: The water temperature will increase by 10 ºС.