How many electrons pass through the cross section of the kettle spiral in 2 minutes, if the current in the kettle’s

How many electrons pass through the cross section of the kettle spiral in 2 minutes, if the current in the kettle’s electric circuit is 3 A, the elementary charge e = 1.6 ∙ 10-19 C?

Task data: t (duration of work) = 2 min = 120 s; I (current in the electric circuit of the kettle in use) = 3 A.

Reference data: according to the condition e (elementary charge) = 1.6 * 10 ^ -19 Cl.

To calculate the number of electrons passing through the spiral of the used kettle, we use the equality: e * n = q (charge) = I * t, from where we express: n = I * t / e.

Calculation: n = 3 * 120 / (1.6 * 10 ^ -19) = 225 * 10 ^ 19 electrons.

Answer: 225 * 10 ^ 19 electrons will pass through the spiral of the teapot used.