How many grams of carbide is required to obtain 56 liters of acetylene.

The equation for the reaction of calcium carbide with water:

CaC2 + 2H2O = Ca (OH) 2 + C2H2

The amount of acetylene substance:

v (C2H2) = V (C2H2) / Vm = 56 / 22.4 = 2.5 (mol).

According to the reaction equation, 1 mol of C2H2 is formed from 1 mol of CaC2, therefore:

v (CaC2) = v (C2H2) = 2.5 (mol).

Thus, the mass of calcium carbide required is:

m (CaC2) = v (CaC2) * M (CaC2) = 2.5 * 64 = 160 (g).

Answer: 160 g.

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