Let’s implement the solution:
In accordance with the condition of the problem, we write down the equation of the process:
X g -? m = 128 g
4HNO3 (conc.) + Cu = 2NO2 + Cu (NO3) 2 + 2H2O – OBP, nitrogen oxide is released (4);
Calculations according to the formulas of substances:
M (HNO3) = 63 g / mol;
M (Cu) = 63.5 g / mol;
Y (Cu) = m / M = 128 / 63.5 = 2 mol.
X mol (HNO3) – 2 mol (Cu);
-4 mol -1 mol hence, X mol (HNO3) = 4 * 2/1 = 8 mol.
Find the mass of acid:
m (HNO3) = Y * M = 8 * 63 = 504 g
Answer: you need nitric acid weighing 504 g
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