How many grams of hydrochloric acid is required to neutralize 24 grams of potassium hydroxide?

We write down the equation of reactions.
HCl + NaOH = NaCl + H2O.
Next, we calculate the molar mass of sodium hydroxide and hydrochloric acid.
M (HCl) = 35.5 + 1 = 36.5 g / mol.
M (NaOH) = 23 + 16 + 1 = 40 g / mol.
Further, according to the reaction equation, we find the mass of hydrochloric acid.
X g HCl – 24 g NaOH.
36.5 g / mol HCl – 40 g / mol NaOH.
Find the unknown value of x.
X = 36.5 × 24 ÷ 40 = 21.9 g.
This means that 21.9 grams of hydrochloric acid will be required.
Answer: m (HCl) = 21.9 g.




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