How many grams of oxygen is needed to obtain 16 g of magnesium oxide MgO: 2Mg + O2 = 2MgO?

Metallic magnesium reacts intensely with oxygen. The reaction is described by the following chemical reaction equation:

Mg + ½ O2 = MgO;

During oxidation, one oxygen atom is attached to the magnesium atom. In this case, one molecule of magnesium oxide is synthesized.

Find the molar amount of magnesium oxide.

Divide the available weight of magnesium oxide by the weight of 1 mole of this substance.

M MgO = 24 + 16 = 40 grams / mol; N MgO = 16/40 = 0.4 mol;

To oxidize this amount of magnesium, 2 times less chemical amount of oxygen is required.

Let’s calculate its weight.

To do this, multiply the amount of the substance by the weight of 1 mole of the substance.

M O2 = 16 x 2 = 32 grams / mol; m O2 = 0.4 / 2 x 32 = 6.4 grams;