How many grams of oxygen will be released during the decomposition of 5 g of potassium chlorate KCLO3?

The mass of potassium chlorate is 5 g.

Let us determine the mass of oxygen obtained as a result of the reaction.

Let us write down the reaction equation for this problem.

2KClO3 = 2KCl + 3O2.

Potassium chlorate decomposes into potassium chlorine and oxygen.

Let us determine the molar mass of potassium chlorate and oxygen.

M (KClO3) = 39 + 35.5 + 16 * 3 = 122.5 g / mol.

M (O2) = 16 * 2 = 32 g / mol.

Using the reaction equation, we determine the mass of oxygen.

5 g of potassium chlorate – x g of oxygen.

2 * 122.5 g / mol – 3 * 32 g / mol.

X = 3 * 32 * 5 / (2 * 122.5) = 1.3 g.

Answer: the mass of oxygen is 1.3 g.




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