How many grams of sodium hydroxide is required to neutralize 200 cm3 of sulfuric acid whose molar

How many grams of sodium hydroxide is required to neutralize 200 cm3 of sulfuric acid whose molar concentration is 0.1 mol / dm3

Given:
V solution (H2SO4) = 200 cm3 = 0.2 l
Cm (H2SO4) = 0.1 mol / dm3 = 0.1 mol / l

To find:
m (NaOH) -?

Decision:
1) Write the equation of a chemical reaction:
H2SO4 + 2NaOH => Na2SO4 + 2H2O;
2) Calculate the amount of substance H2SO4:
n (H2SO4) = Cm (H2SO4) * V solution (H2SO4) = 0.1 * 0.2 = 0.02 mol;
3) Determine the amount of NaOH substance:
n (NaOH) = n (H2SO4) * 2 = 0.02 * 2 = 0.04 mol;
4) Calculate the mass of NaOH:
m (NaOH) = n (NaOH) * M (NaOH) = 0.04 * 40 = 1.6 g.

Answer: The mass of sodium NaOH is 1.6 g.