How many grams of sodium hydroxide is required to neutralize 200 cm3 of sulfuric acid whose molar concentration is 0.1 mol / dm3
V solution (H2SO4) = 200 cm3 = 0.2 l
Cm (H2SO4) = 0.1 mol / dm3 = 0.1 mol / l
m (NaOH) -?
1) Write the equation of a chemical reaction:
H2SO4 + 2NaOH => Na2SO4 + 2H2O;
2) Calculate the amount of substance H2SO4:
n (H2SO4) = Cm (H2SO4) * V solution (H2SO4) = 0.1 * 0.2 = 0.02 mol;
3) Determine the amount of NaOH substance:
n (NaOH) = n (H2SO4) * 2 = 0.02 * 2 = 0.04 mol;
4) Calculate the mass of NaOH:
m (NaOH) = n (NaOH) * M (NaOH) = 0.04 * 40 = 1.6 g.
Answer: The mass of sodium NaOH is 1.6 g.
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