How many grams of sodium hydroxide is required to obtain 33.6 liters of methane from sodium acetate.

Given:
V (CH4) = 33.6 L

To find:
m (NaOH) -?

Decision:
1) Write the reaction equation:
CH3COONa + NaOH => CH4 + Na2CO3;
2) Calculate the amount of substance CH4:
n (CH4) = V (CH4) / Vm = 33.6 / 22.4 = 1.5 mol;
3) Determine the amount of NaOH substance:
n (NaOH) = n (CH4) = 1.5 mol;
4) Calculate the molar mass of NaOH:
M (NaOH) = Mr (NaOH) = Ar (Na) * N (Na) + Ar (O) * N (O) + Ar (H) * N (H) = 23 * 1 + 16 * 1 + 1 * 1 = 40 g / mol;
5) Calculate the mass of NaOH:
m (NaOH) = n (NaOH) * M (NaOH) = 1.5 * 40 = 60 g.

Answer: The mass of NaOH is 60 g.