How many grams of sulfuric acid and barium chloride will it take to produce 4.66 g of barium sulfate?

Barium chloride reacts with sulfuric acid. This forms a water-insoluble barium sulfate salt, which precipitates. The reaction is described by the following chemical reaction equation.

BaCl2 + H2SO4 = BaSO4 + 2HCl;

Barium chloride reacts with sulfuric acid in equal molar amounts. In this case, the same amount of insoluble barium sulfate is synthesized.

Find the chemical amount of barium sulfate.

M BaSO4 = 137 + 32 + 16 x 4 = 233 grams / mol; N BaSO4 = 4.66 / 233 = 0.02 mol;

Let’s find the weight of this amount of sulfuric acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol; m H2SO4 = 0.02 x 98 = 1.96 grams;

Let’s calculate the weight of this amount of barium chloride.

M BaCl2 = 137 + 35.5 x 2 = 208 grams / mol; m BaCl2 = 0.02 x 208 = 4.16 grams;