How many grams of water is formed from 112 liters of oxygen?

Given:
V (O2) = 112 l

To find:
m (H2O) -?

Solution:
1) O2 + 2H2 => 2H2O;
2) n (O2) = V (O2) / Vm = 112 / 22.4 = 5 mol;
3) n (H2O) = n (O2) = 5 * 2 = 10 mol;
4) m (H2O) = n (H2O) * M (H2O) = 10 * 18 = 180 g.

Answer: The mass of H2O is 180 g.

 



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