Reaction equation: CaCO3 = CaO + CO2
According to the periodic table, we determine the molar mass of calcium carbonate M = 40 + 12 + 16 * 3 = 100 g / mol. And the molar mass of calcium oxide is M = 40 + 16 = 56 g / mol. Let us find the amount of calcium carbonate substance n = m / M = 250,000 g / 100 g / mol = 2500 mol. According to the reaction, 1 mol of calcium oxide is formed from 1 mol of carbonate, n (CaCO3) = n (CaO) = 2500 mol. Let’s find the mass of calcium oxide m = n * M = 2500 mol * 56 g / mol = 140 000 g = 140 kg.
Answer: 140 kg of calcium oxide is formed.
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