How many liters of carbon dioxide are produced by burning 4.2 g of propene?

To solve the problem, we compose the equation:
m = 4.2 g. X g -?
1. 2С3Н6 + 9О2 = 6СО2 + 6Н2О + Q – combustion, obtained carbon monoxide (4), water;
2. Calculations:
M (C3H6) = 42 g / mol.
M (CO2) = 44 g / mol.
3. Determine the amount of the original substance:
Y (C3H6) = m / M = 4, 2/42 = 0.1 mol.
4. Proportion:
0.1 mol (C3H6) – X mol (CO2);
– 2 mol – 6 mol from here, X mol (CO2) = 0.1 * 6/2 = 0.3 mol.
5. Find the volume of the product:
V (CO2) = 0.3 * 22.4 = 6.72 liters.
Answer: carbon monoxide (4) is released with a volume of 6.72 liters.




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