How many liters of carbon dioxide (carbon dioxide) will be released when burning 4 tons of propane?

How many liters of carbon dioxide (carbon dioxide) will be released when burning 4 tons of propane? How many liters of oxygen will this be consumed?

СЗН8 + 5О2 = 3СО2 + 4Н2О
(C3H8) = m / M = 4 * 10 ^ 6/44 = 90 909 mol
v (О2) = 5 * v (C3H8) = 5 * 90909 = 454545 mol
v (O2) = 454545 * 22.4 = 10 181 808 l
v (CO2) = 90909 * 3 * 22.4 = 6 109 085 l
Answer: v (O2) = 10 181 808 l
v (CO2) = 6 109 085 l



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