How many liters of cl2 will react with 200 g of butadiene?

To solve the problem, write down the equation:
m = 200 g. X l. -?
1. H2C = CH – CH = CH2 + Cl2 = CH2Cl – CH = CH – CH2Cl – addition reaction, dichloroethene was obtained;
2. Calculation of molar masses:
M (C4H6) = 54 g / mol;
M (Cl2) = 71 g / mol.
3. Find the number of moles of butadiene, if the mass is known:
Y (C4H6) = m / M = 200/54 = 3.7 mol;
Y (Cl2) = 3.7 mol since the amount of these substances according to the equation is 1 mol.
4.Calculate the amount of chlorine using Avogadro’s law:
V (Cl2) = 3.7 * 22.4 = 82.88 liters.
Answer: to carry out the reaction, chlorine with a volume of 82.88 liters is required.




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