Based on the condition of the problem, we write down the equation of the process:
Na2CO3 + H2SO4 = Na2SO4 + CO2 + H2O – ion exchange, carbon dioxide is released;
Let’s make the calculations:
M (Na2CO3) = 105.8 g / mol;
M (CO2) = 44 g / mol.
Determine the amount of the original substance, if the mass is known:
Y (Na2CO3) = m / M = 28 / 105.8 = 0.26 mol;
Y (CO2) = 0.26 mol since the amount of substances is 1 mol.
Find the volume of carbon monoxide:
V (CO2) = 0.26 * 22.4 = 5.8 L
Answer: received carbon monoxide (4) with a volume of 5.8 liters
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