How many liters of gas are released when 28 grams of sodium carbonate is dissolved in sulfuric acid?

Based on the condition of the problem, we write down the equation of the process:

Na2CO3 + H2SO4 = Na2SO4 + CO2 + H2O – ion exchange, carbon dioxide is released;
Let’s make the calculations:
M (Na2CO3) = 105.8 g / mol;

M (CO2) = 44 g / mol.

Determine the amount of the original substance, if the mass is known:
Y (Na2CO3) = m / M = 28 / 105.8 = 0.26 mol;

Y (CO2) = 0.26 mol since the amount of substances is 1 mol.

Find the volume of carbon monoxide:
V (CO2) = 0.26 * 22.4 = 5.8 L

Answer: received carbon monoxide (4) with a volume of 5.8 liters