How many liters of hydrogen will be obtained by reacting 6 g of acetic acid with magnesium

How many liters of hydrogen will be obtained by reacting 6 g of acetic acid with magnesium if the hydrogen yield is 60 percent?

Metallic magnesium dissolves in acetic acid solution. The chemical reaction proceeds according to the following equation:

Mg + 2CH3COOH = Mg (CH3COO) 2 + H2 ↑;

Let’s determine the chemical amount of acetic acid.

To do this, divide its weight by the weight of 1 mole of acid.

M CH3COOH = 12 x 2 + 16 x 2 + 4 = 60 grams / mol;

N CH3COOH = 6/60 = 0.1 mol;

2 times less hydrogen will be synthesized.

Let’s find the volume of hydrogen.

For this purpose, we multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V H2 = 0.1 / 2 x 22.4 = 1.12 liters;

Taking into account the reaction yield of 60%, the volume of hydrogen will be 1.12 x 0.6 = 0.672 liters;




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