How many liters of hydrogen will be released when hydrochloric acid interacts with 2.7 aluminum.

The reaction of aluminum with hydrochloric acid is described by the following formula:

2Al + 6HCl = 2AlCl3 + 3H2;

From 2 moles of aluminum, 3 moles of hydrogen are formed.

The molar mass of aluminum is 27 grams / mol.

Accordingly, 2.7 grams contain 2.7 / 27 = 0.1 mol of the substance.

With that amount of aluminum, you can get 0.1 x 3/2 = 0.15 mol of hydrogen.

Under normal conditions, 1 mole of ideal gas takes up a volume of 22.4 liters.

0.15 mol of hydrogen occupies a volume of 0.15 x 22.4 = 3.36 liters.

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