How many liters of oxygen do you need to burn 5.6 liters of methane?

To solve, we write down data on the condition of the problem:

СН4 + 2О2 = СО2 + 2Н2О + Q – combustion, carbon monoxide, water, heat are released;
Proportions:
1 mol of gas at normal level – 22.4 l
X mol (CH4) -5.6 L from here, X mol (CH4) = 1 * 5.6 / 22.4 = 0.25 mol;

0.25 mol (CH4) – X mol (O2);

-1 mol -2 mol from here, X mol (O2) = 0.25 * 2/1 = 0.5 mol.

We find the volume of O2:
V (O2) = 0.5 * 22.4 = 11.2 L

Answer: you need oxygen with a volume of 11.2 liters



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