Let’s write down given:
m (NaOH) = 24g
n (Na2SO4) -?
The reaction between an acid and a base to form salt and water is called a neutralization reaction. Therefore, to obtain sodium sulfate, we must take sodium hydroxide and sulfuric acid.
Let’s write the reaction equation:
2 NaOH + H2SO4 = Na2SO4 + 2H2O;
Find the amount of sodium hydroxide substance:
n (NaOH) = m (NaOH) / M (NaOH);
M (NaOH) = 23 + 16 + 1 = 40 g / mol;
n (NaOH) = 24 g / 40 g / mol = 0.6 mol
Let’s calculate the amount of sodium sulfate substance:
From 2 mol (NaOH) 1 mol (Na2SO4) is formed
From 0.6 mol (NaOH) x mol (Na2SO4) is formed
X = 0.6 mol * 1 mol / 2 mol = 0.3 mol;
Answer: 0.3 mol (Na2SO4).
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