How many moles of sodium sulfate can be obtained from 24 g of NaOH by the neutralization reaction?

Let’s write down given:

m (NaOH) = 24g

n (Na2SO4) -?


The reaction between an acid and a base to form salt and water is called a neutralization reaction. Therefore, to obtain sodium sulfate, we must take sodium hydroxide and sulfuric acid.

Let’s write the reaction equation:

2 NaOH + H2SO4 = Na2SO4 + 2H2O;

Find the amount of sodium hydroxide substance:

n (NaOH) = m (NaOH) / M (NaOH);

M (NaOH) = 23 + 16 + 1 = 40 g / mol;

n (NaOH) = 24 g / 40 g / mol = 0.6 mol

Let’s calculate the amount of sodium sulfate substance:

From 2 mol (NaOH) 1 mol (Na2SO4) is formed

From 0.6 mol (NaOH) x mol (Na2SO4) is formed

X = 0.6 mol * 1 mol / 2 mol = 0.3 mol;

Answer: 0.3 mol (Na2SO4).

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