To find the required number of oscillations made by the taken pendulum, we use the equality: 2Π * √ (l / g) = T = t / n, whence we express: n = t / (2Π * √ (l / g)).
Values of variables and constants: t – time of oscillation of the pendulum (t = 40 s); l is the length of the pendulum (l = 3.6 m); g – acceleration due to gravity (g ≈ 10 m / s).
Calculation: n = t / (2Π * √ (l / g)) = 40 / (2 * 3.14 * √ (3.6 / 10)) ≈ 10.62 oscillations.
Answer: In 40 seconds, the taken pendulum must make 10.62 oscillations.
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