How many oscillations will the pendulum make in 40 seconds if the length is 3.6m?

To find the required number of oscillations made by the taken pendulum, we use the equality: 2Π * √ (l / g) = T = t / n, whence we express: n = t / (2Π * √ (l / g)).

Values of variables and constants: t – time of oscillation of the pendulum (t = 40 s); l is the length of the pendulum (l = 3.6 m); g – acceleration due to gravity (g ≈ 10 m / s).

Calculation: n = t / (2Π * √ (l / g)) = 40 / (2 * 3.14 * √ (3.6 / 10)) ≈ 10.62 oscillations.

Answer: In 40 seconds, the taken pendulum must make 10.62 oscillations.