How many times is the force of electrical repulsion between two electrons greater

| July 31, 2021 | education

How many times is the force of electrical repulsion between two electrons greater than the force of their gravitational attraction to each other?

To calculate the ratio of the forces of electric repulsion and gravitational attraction of electrons, we use the formula: n = (k * qe ^ 2 / r ^ 2) / (G * me ^ 2 / r ^ 2) = k * qe ^ 2 / (G * me ^ 2).

Constants: k – proportionality coefficient (k = 9 * 10 ^ 9 m / F); qe – electron charge (qe = -1.6 * 10 ^ -19 C); G (gravitational constant) ≈ 6.674 * 10 ^ -11 m3 / (s2 * kg); me is the mass of an electron (me = 9.11 * 10 ^ -31 kg).

Calculation: n = k * qe ^ 2 / (G * me ^ 2) = 9 * 10 ^ 9 * (1.6 * 10 ^ -19) ^ 2 / (6.674 * 10 ^ -11 * (9.11 * 10 ^ -31) ^ 2) = 4.16 * 10 ^ 42 p.

Answer: The force of electrical repulsion is 4.16 * 10 ^ 42 times greater.



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