# How many times is the force of electrical repulsion between two electrons greater

How many times is the force of electrical repulsion between two electrons greater than the force of their gravitational attraction to each other?

To calculate the ratio of the forces of electric repulsion and gravitational attraction of electrons, we use the formula: n = (k * qe ^ 2 / r ^ 2) / (G * me ^ 2 / r ^ 2) = k * qe ^ 2 / (G * me ^ 2).

Constants: k – proportionality coefficient (k = 9 * 10 ^ 9 m / F); qe – electron charge (qe = -1.6 * 10 ^ -19 C); G (gravitational constant) ≈ 6.674 * 10 ^ -11 m3 / (s2 * kg); me is the mass of an electron (me = 9.11 * 10 ^ -31 kg).

Calculation: n = k * qe ^ 2 / (G * me ^ 2) = 9 * 10 ^ 9 * (1.6 * 10 ^ -19) ^ 2 / (6.674 * 10 ^ -11 * (9.11 * 10 ^ -31) ^ 2) = 4.16 * 10 ^ 42 p.

Answer: The force of electrical repulsion is 4.16 * 10 ^ 42 times greater. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.