# How many times is the force of electrical repulsion between two electrons greater

**How many times is the force of electrical repulsion between two electrons greater than the force of their gravitational attraction to each other?**

To calculate the ratio of the forces of electric repulsion and gravitational attraction of electrons, we use the formula: n = (k * qe ^ 2 / r ^ 2) / (G * me ^ 2 / r ^ 2) = k * qe ^ 2 / (G * me ^ 2).

Constants: k – proportionality coefficient (k = 9 * 10 ^ 9 m / F); qe – electron charge (qe = -1.6 * 10 ^ -19 C); G (gravitational constant) ≈ 6.674 * 10 ^ -11 m3 / (s2 * kg); me is the mass of an electron (me = 9.11 * 10 ^ -31 kg).

Calculation: n = k * qe ^ 2 / (G * me ^ 2) = 9 * 10 ^ 9 * (1.6 * 10 ^ -19) ^ 2 / (6.674 * 10 ^ -11 * (9.11 * 10 ^ -31) ^ 2) = 4.16 * 10 ^ 42 p.

Answer: The force of electrical repulsion is 4.16 * 10 ^ 42 times greater.