How many times the mean square velocity of helium molecules at 200K differs from the mean

How many times the mean square velocity of helium molecules at 200K differs from the mean square velocity of this gas at 800K

To calculate the difference in the root mean square velocities of helium molecules at given temperatures, we use the formula: n = √ (3R * Tc / MHe) / √ (3R * Tn / MHe) = √ (Tc / Tn).

Variables: Tк – the second temperature of helium (Tк = 800 К); Tn – the first temperature (Tn = 200 K).

Let’s calculate: n = √ (Tc / Tn) = √ (800/200) = 2 p.

Answer: With abs. at a temperature of 200 K, the root-mean-square velocity of helium molecules is 2 times less.