How many times will the pressure of an ideal gas increase if the mean square velocity of its small molecules doubles?
| September 28, 2021 | education
To determine the increase in pressure of the specified ideal gas, we use the ratio: n = Рк / Рн = (ρ * Vк ^ 2/3) / (ρ * Vн ^ 2/3) = Vк ^ 2 / Vн2 = (Vк / Vн) ^ 2 …
Variable ratios: Vk (increased root mean square speed) = 2Vn (initial root mean square speed).
Let’s make a calculation: n = (Vk / Vn) ^ 2 = (2Vn / Vn) ^ 2 = 2 ^ 2 = 4 p.
Answer: The pressure of the specified ideal gas will increase by 4 times.
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