How much acetaldehyde can be obtained from 400 kg of calcium carbide containing 10% impurities

To solve the problem, we compose the equations of the processes:

CaC2 + 2H2O = Ca (OH) 2 + C2H2 – hydration, acetylene formed;
С2Н2 + Н2О = Н2С = СНОН (vinyl alcohol) = СН3 – СОН – acetaldehyde was obtained.
Calculations:
m (CaC2) = 400 kg = 400,000 g;

M (CaC2) = 64 g / mol;

M (C2H4O) = 44 g / mol;

m (CaC2) = 400000 (1 – 0.10) = 3600000 g (weight without impurity);

Y (CaC2) = m / M = 3600000/64 = 56250 mol;

Y (C2H4O) = 56250 mol since the amount of substances is 1 mol.

3. Find the mass of the aldehyde:

m (C2H4O) = Y * M = 56250 * 44 = 2475000 g = 2475 kg

Answer: the mass of acetaldehyde is 2475 kg