To solve the problem, we compose the equations of the processes:
CaC2 + 2H2O = Ca (OH) 2 + C2H2 – hydration, acetylene formed;
С2Н2 + Н2О = Н2С = СНОН (vinyl alcohol) = СН3 – СОН – acetaldehyde was obtained.
m (CaC2) = 400 kg = 400,000 g;
M (CaC2) = 64 g / mol;
M (C2H4O) = 44 g / mol;
m (CaC2) = 400000 (1 – 0.10) = 3600000 g (weight without impurity);
Y (CaC2) = m / M = 3600000/64 = 56250 mol;
Y (C2H4O) = 56250 mol since the amount of substances is 1 mol.
3. Find the mass of the aldehyde:
m (C2H4O) = Y * M = 56250 * 44 = 2475000 g = 2475 kg
Answer: the mass of acetaldehyde is 2475 kg
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