How much acetylene needs to be spent to obtain benzene weighing 40 kg?

Let’s make the equation:
3C2H2 = C6H6 – acetylene trimerization reaction occurs on hot coal, benzene is released;
Let’s calculate the molar mass of benzene:
M (C6H6) = 12 * 6 + 6 = 82 g / mol;
Let us determine the number of moles of benzene if its mass is known:
m (C6H6) = 40 kg = 40,000 g; Y (C6H6) = m (C6H6) / M (C6H6); Y (C6H6) = 487.8 mol;
Let’s make the proportion:
X mol (C2H4) – 487.8 mol (C6H6);
-3 mol -1 mol hence, X mol (C2H4) = 487.8 * 3 = 1463.4 mol;
Let’s calculate the volume of ethylene according to Avogadro’s law:
V (C2H4) = 1463.4 * 22.4 = 32780 hp
Answer: to obtain benzene, ethylene is needed in a volume of 32,780 liters.

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