How much carbon dioxide reacted with barium hydroxide if 157.6 g of barium carbonate were then formed, which is 80% of the theoretical yield.
Let’s find how much barium carbonate should be obtained according to theory.
157.6 g – 100%,
X g – 80%.
X = (157.6 g × 80%): 100% = 197 g.
Find the amount of barium carbonate substance by the formula:
n = m: M.
M (BaCO3) = 137 + 12 + 48 = 197 g / mol.
n = 197 g: 197 g / mol = 1 mol.
Let’s compose the reaction equation, find the quantitative ratios of substances.
Ba (OH) 2 + CO2 = BaCO3 + H2O.
According to the reaction equation, 1 mole of barium carbonate accounts for 1 mole of carbon dioxide. Substances are in quantitative ratios 1: 1.
The amount of the substance barium carbonate and carbon dioxide will be equal.
n (ВаСО3) = n (СО2) = 1 mol.
Let’s find the volume of hydrogen.
V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.
V = 1 mol × 22.4 L / mol = 22.4 L.
Answer: 22.4 liters.