How much co2 can be obtained from the decomposition of 200 g of limestone containing 20% of impurities?

The decomposition reaction of calcium carbonate is described by the following chemical reaction equation:

CaCO3 = CaO + CO2;

From one mole of calcium carbonate, one mole of calcium oxide and carbon monoxide is formed.

Determine the mass of pure calcium carbonate.

m CaCO3 = 200 x 90% = 180 grams;

Determine the amount of substance in 180 grams of calcium carbonate.

Its molar mass is:

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

The amount of the substance will be:

N CaCO3 = 180/100 = 1.8 mol;

The same amount of carbon monoxide and calcium oxide will be obtained.

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

Let’s determine the volume of carbon dioxide:

V CO2 = 1.8 x 22.4 = 40.32 liters;