To calculate the required weight of 18.75 liters of kerosene, we use the formula: P = m * g = ρк * V * g.
Constants and variables: ρк – kerosene density (ρк = 800 kg / m3); V is the volume of kerosene (V = 18.75 l = 0.01875 m3); g – acceleration due to gravity (g ≈ 10 m / s2).
Calculation: P = ρк * V * g = 800 * 0.01875 * 10 = 150 N.
Answer: Kerosene, which takes up a volume of 18.75 liters, should have a weight of 150 N.
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