T1 = 600 degrees Celsius – the initial temperature of the steel part;
T2 = 100 degrees Celsius – the final temperature of the steel part;
m = 800 grams = 0.8 kilograms is the mass of the steel part;
c = 500 J / (kg * C) – specific heat capacity of steel.
It is required to determine Q (Joule) – how much energy is released when cooling a steel part from T1 to T2.
Q = c * m * (T1 – T2) = 500 * 0.8 * (600 – 100) = 500 * 0.8 * 500 =
= 250,000 * 0.8 = 200,000 Joules = 200 kJ.
Answer: when the steel part is cooled, an energy equal to 200 kJ will be released.
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